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LESSON 18 / 21 · TOPIC 2.9

Why does a quotient’s derivative subtract?

You will be able to: Apply the quotient rule in the correct order with a squared denominator.

Graphs, tables and mathematical reasoningFree study resourceReview editionTeacher review pending

BC foundation: Unit 2 shares its derivative foundations with AB. Connect each rule to rates, graphs and its domain conditions. Use the written challenges to explain your reasoning. Chain-rule compositions, implicit and inverse differentiation, and advanced applications come later.

Why does a quotient’s derivative subtract?

A ratio can fall because its denominator increases even if its numerator stays fixed. That opposing effect explains the subtraction in its derivative.

A useful starting point: How do you differentiate a product without formulas? →

Words and symbols before equations

Quotient
A ratio u/v with v≠0.
Numerator
The top function u.
Denominator
The bottom function v.
Quotient rule
Derivative (u′v−uv′)/v², where both functions are differentiable and v≠0.
Ratio q=(x²+1)/(x+1)-3-8-1.5-4001.5438x (dimensionless)y (dimensionless)P
Read this model snapshot. a=1; q(a)=1; q′(a)=0.5. Orange: tangent; blue: ratio. x=−1 remains excluded. Off-window tangent/curve portions are clipped.
What this picture assumes

Original equation-driven model; readouts are rounded. Graphs have labeled linear scales and finite sampled windows; algebra supplies exact conclusions. q=(x²+1)/(x+1), x≠−1. The fixed graph splits at −1. The control samples only the right branch; no finite value is assigned at the asymptote.

Read the picture in three steps

  1. Read the axes and labels first. Identify what each symbol and line represents. Read the units and fixed conditions before comparing quantities.
  2. a=1; q(a)=1; q′(a)=0.5. Orange: tangent; blue: ratio. x=−1 remains excluded. Off-window tangent/curve portions are clipped.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the mathematics

Let q=u/v, so u=qv. Applying the product rule gives u′=q′v+qv′. Solving for q′ and replacing q by u/v yields (u′v−uv′)/v².

For u=x²+1 and v=x+1, u′=2x and v′=1. The numerator is 2x(x+1)−(x²+1), with parentheses preserving the subtraction.

The denominator is (x+1)², not its derivative. The original denominator must be nonzero, so x=−1 stays excluded.

A constant numerator gives a negative contribution −uv′/v². A constant denominator gives u′/v, consistent with constant-multiple differentiation.

A worked example, step by step

Find the derivative of (x²+1)/(x+1) at x=1.

  1. Identify u= x²+1, u′=2x, v=x+1 and v′=1.
  2. Write q′=[2x(x+1)−(x²+1)]/(x+1)².
  3. At 1 the numerator is 4−2=2 and denominator is 4.
  4. Therefore q′(1)=1/2; the formula is valid for x≠−1.
Common mix-up

Keep the order u′v−uv′. Reversing it negates the correct derivative.

CHECK THE IDEA

Is (u/v)′ equal to u′/v′?

Compare with an explanation

No. For u=x and v=x, the ratio is 1 where defined, so its derivative is 0, while u′/v′ would be 1.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Move the evaluation input on a valid branch. Compare both numerator contributions and explain why the difference can change sign.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Ratio q=(x²+1)/(x+1)-3-8-1.5-4001.5438x (dimensionless)y (dimensionless)P

a=1; q(a)=1; q′(a)=0.5. Orange: tangent; blue: ratio. x=−1 remains excluded. Off-window tangent/curve portions are clipped.

Quotient-rule components at selected au=2; u′=2v=2; v′=1u′v−uv′=2v²=4; derivative=0.5

Original equation-driven model; readouts are rounded. Graphs have labeled linear scales and finite sampled windows; algebra supplies exact conclusions. q=(x²+1)/(x+1), x≠−1. The fixed graph splits at −1. The control samples only the right branch; no finite value is assigned at the asymptote.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using a difference quotient, tangent slope, or derivative rule with its domain conditions. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. At a, u=6,u′=2,v=3,v′=1. The quotient derivative is…

Show answer and reasoning

0. (2·3−6·1)/3²=0.

2. The denominator of the quotient derivative is…

Show answer and reasoning

v². It is the square of the original bottom function.

Original written challenge

4 points · self-check · not an official AP question

Differentiate q(x)=(x+2)/(x−1), state its domain restriction and evaluate q′(2).

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: Let u=x+2 and v=x−1; both derivatives equal 1.
  2. 1 point: Numerator=(x−1)−(x+2)=−3.
  3. 1 point: q′=−3/(x−1)² for x≠1.
  4. 1 point: At 2, q′(2)=−3.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1Quotient-rule numerator order?

Top derivative times bottom, minus top times bottom derivative.

RECALL 2Which denominator gets squared?

The original v, not v′.

RECALL 3Why require v≠0?

The original ratio must be defined.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Why does a quotient’s derivative subtract?

  • (u/v)′=(u′v−uv′)/v², v≠0.

Remember: Keep the order u′v−uv′. Reversing it negates the correct derivative.

Conditions: Original equation-driven model; readouts are rounded. Graphs have labeled linear scales and finite sampled windows; algebra supplies exact conclusions. q=(x²+1)/(x+1), x≠−1. The fixed graph splits at −1. The control samples only the right branch; no finite value is assigned at the asymptote.

Refresh Kid · AP Calculus BC Unit 2 · Objectives FUN-3.B · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 2.9, FUN-3.B. CED effective Fall 2020, with Fall 2026 clarifications, checked September 17, 2026. Unit 2 has 10 official topics. Focused lesson titles and questions are original Refresh Kid teaching material.

Derivative definitions require finite two-sided limits at interior inputs. Graphs and finite tables supply evidence and estimates, not universal proofs. Continuity is necessary but insufficient for differentiability. Rules retain their original domain restrictions, and trigonometric inputs use radians. Chain-rule compositions, implicit differentiation, inverse-function differentiation and L’Hôpital’s rule are deferred to later units. Piecewise joins are checked for continuity before their side slopes are compared.

The Organic Chemistry Tutor video titles, creators and descriptions were checked; full videos were not reviewed. Khan Academy’s unit destination was checked; its JavaScript lesson content was not fully readable by the research tool. OpenStax Sections 3.1, 3.3 and 3.5 were consulted for conceptual cross-checking. No creator scripts, questions, diagrams or artwork were copied. Refresh Kid is not endorsed by these providers.

GitHub’s 3D website collection and its camera-control example informed optional spatial inspection. Graph geometry is generated from the stated original equations; self-hosted Three.js retains its MIT license. The optional 3D model uses separate planes for f and f′. Depth distinguishes panels, not an additional variable; camera rotation does not change their values. Use the complete labeled 2D graphs and text to read precise coordinates and slopes.

Independent teacher review and observation of students remain pending. Checks do not certify scientific accuracy, accessibility or learning effectiveness. This is a review edition.

Optional official resource: Released AP Calculus BC questions and scoring guides. The archive spans multiple units; no entire exam question is assigned to this lesson.

Learn → Explore → Practice → Review is informed by the IES learning guide; this exact implementation has not been evaluated with learners.

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