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LESSON 04 / 20 · TOPIC 8.2

Track the electrons across the system boundary

You will be able to: Use a charge ledger for friction or contact without creating charge.

Calculus-based electrostaticsFree study resourceReview editionTeacher review pending

Where does the charge come from when objects become charged?

When two initially neutral objects exchange electrons, the donor becomes positive and the receiver becomes negative. Their combined net charge remains zero if nothing enters or leaves the pair.

A useful starting point: A material can polarize without gaining charge →

Words and symbols before equations

System boundary
The boundary deciding which objects belong in your charge total.
Electron transfer
Moving negatively charged electrons from one object to another.
Conservation of charge
Total charge remains fixed for a system with no charge transfer across its boundary.
Frictional charging
Contact and separation of materials can transfer charge; rubbing does not create it.
Charge after electron transfernC · same scale for all bars0Object A8Object B-8Pair total0
Read this model snapshot. 50 billion signed electrons A → B. Final A 8 nC; B -8 nC; pair total 0 nC, unchanged from its initial value.
What this picture assumes

Positive transfer means electrons move from A to B; negative transfer reverses it. The pair is isolated. One billion electrons carry −0.16 nC using e = 1.60 × 10⁻¹⁹ C.

Read the picture in three steps

  1. Locate the labeled sources, system boundary or graph axes. Read the units before comparing values.
  2. 50 billion signed electrons A → B. Final A 8 nC; B -8 nC; pair total 0 nC, unchanged from its initial value.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the physics

For N electrons moving from A to B, ΔQ_A = +Ne and ΔQ_B = −Ne. Losing negative charge makes A more positive. Add the changes to see that ΔQ_A + ΔQ_B = 0.

An individual object is an open system during transfer, even if the two-object pair is isolated. For any chosen system, Q_final = Q_initial + Q_entering − Q_leaving, with signed charge values.

Contact between identical isolated conducting spheres can equalize their charges when their surroundings are symmetric and they are then separated. Arbitrary objects need not split the charge equally; shape and environment matter.

A worked example, step by step

Two neutral objects exchange 5 × 10¹⁰ electrons from A to B. Find their final charges using e = 1.60 × 10⁻¹⁹ C.

  1. Choose both objects as the isolated system; initial total charge is zero.
  2. The transferred magnitude is Ne = (5 × 10¹⁰)(1.60 × 10⁻¹⁹) = 8.0 × 10⁻⁹ C.
  3. A loses electrons: Q_A = +8.0 nC. B gains them: Q_B = −8.0 nC.
  4. The total remains +8.0 − 8.0 = 0 nC. Each object changed; the pair did not.
Common mix-up

Objects gain positive net charge by losing electrons in these examples, not by manufacturing protons.

CHECK THE IDEA

Can A’s charge change while the pair’s charge stays fixed?

Compare with an explanation

Yes. Transfer inside the pair changes the distribution but not the pair’s total.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Move the signed transfer control through zero. Positive values mean electrons go A → B; negative values reverse the transfer. Check the total after every change.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Charge after electron transfernC · same scale for all bars0Object A8Object B-8Pair total0

50 billion signed electrons A → B. Final A 8 nC; B -8 nC; pair total 0 nC, unchanged from its initial value.

Charge changes within the isolated pairnC · same scale for all bars0ΔQ_A8ΔQ_B-8Total change0

Positive transfer means electrons move from A to B; negative transfer reverses it. The pair is isolated. One billion electrons carry −0.16 nC using e = 1.60 × 10⁻¹⁹ C.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use the relevant charge, vector superposition, electric field, flux or symmetry relationship to justify your prediction.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. An object gains electrons. Its net charge becomes…

Show answer and reasoning

more negative. Electrons carry negative charge.

2. An isolated pair begins with total +6 nC. After contact its total is…

Show answer and reasoning

+6 nC. Contact can redistribute charge but cannot change the isolated total.

Original written challenge

4 points · self-check · not an official AP question

A starts at +3 nC and B at −1 nC. Electrons carrying a magnitude of 2 nC move from B to A. Find final charges and check conservation.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: A gains negative charge, so ΔQ_A = −2 nC.
  2. 1 point: Q_A,final = +1 nC.
  3. 1 point: B loses negative charge, so Q_B,final = +1 nC.
  4. 1 point: Final total is +2 nC, equal to the initial +3 − 1 = +2 nC.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What does losing electrons do?

It makes net charge more positive.

RECALL 2What must be specified before applying conservation?

The system boundary and any charge transfer across it.

RECALL 3Does contact always divide charge equally?

No. Equal sharing requires appropriate identical-conductor symmetry.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Track the electrons across the system boundary

  • ΔQ_A = +Ne and ΔQ_B = −Ne for electron transfer A → B.
  • Q_total is constant when no charge crosses the system boundary.
  • 1 nC = 10⁻⁹ C.

Remember: Objects gain positive net charge by losing electrons in these examples, not by manufacturing protons.

Conditions: Positive transfer means electrons move from A to B; negative transfer reverses it. The pair is isolated. One billion electrons carry −0.16 nC using e = 1.60 × 10⁻¹⁹ C.

Refresh Kid · AP Physics C: Electricity and Magnetism Unit 1 (official Unit 8) · Objectives 8.2.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 8.2, objectives 8.2.A. CED effective Fall 2024, current PDF ©2026; checked September 16, 2026. This is E&M Unit 1: Electric Charges, Fields, and Gauss’s Law, numbered Unit 8 in the official combined Physics C sequence. Topics 8.1–8.6 retain their official identifiers. Quantitative force examples use at most four point charges. Field integrals use the specified rods, ring, arc and infinite wire; Gauss-law field calculations use spherical, cylindrical or planar symmetry. Optional projected 3D views clarify area normals and geometry; camera rotation never changes the physics. Checked with the Fall 2026 clarifications. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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