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LESSON 02 / 17 · TOPIC 9.1

Count each charge pair exactly once

You will be able to: Sum unique pair energies and verify the result by sequential assembly.

Calculus-based electrostaticsFree study resourceReview editionTeacher review pending

How much energy does it take to assemble three charges?

Bring the first charge into empty space: there is no interaction energy yet. The second interacts with the first. The third interacts with both charges already present. Three charges create three unique pairs.

A useful starting point: Potential energy belongs to the pair of charges →

Words and symbols before equations

Unique pair
One interaction between two different charges, counted once.
Assembly work
External work to build a configuration slowly from infinite separation.
Separation r_ij
Distance between charges i and j.
Fixed configuration
Charge positions are specified and held; this calculation is not a motion simulation.
Three distinct pair contributionsJ · same scale for all bars0Pair 1–20.009Pair 1–3-0.009Pair 2–3-0.009
Read this model snapshot. Equilateral side 1 m. Total U = -0.009 J. Each pair appears once; the first charge has zero assembly interaction work.
What this picture assumes

Three held point charges on an equilateral triangle; zero interaction energy at infinite separation. Unique pair energies only, with no point-charge self-energy. Positions are fixed; this is not a motion simulation.

Read the picture in three steps

  1. Locate the labeled sources, system boundary or graph axes. Read the units before comparing values.
  2. Equilateral side 1 m. Total U = -0.009 J. Each pair appears once; the first charge has zero assembly interaction work.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the physics

For three charges, U = kq₁q₂/r₁₂ + kq₁q₃/r₁₃ + kq₂q₃/r₂₃. Each term is signed. Do not add magnitudes or include a point charge’s divergent self-energy.

The same answer comes from bringing in each new charge against the potential of charges already assembled. The first costs zero, the second contributes the 1–2 pair, and the third contributes pairs 1–3 and 2–3.

Assembly order does not change the final electrostatic energy. If all q_iV_other,i terms are summed, every pair appears twice; use U = ½Σq_iV_other,i. This factor does not belong in the energy qV of a single probe in fixed source potential.

A worked example, step by step

Charges +1 μC, +1 μC and −1 μC occupy an equilateral triangle of side 1 m. Find total energy.

  1. List the three pairs: 1–2, 1–3, 2–3.
  2. Their energies are +0.009 J, −0.009 J and −0.009 J.
  3. Add signed values: U = −0.009 J.
  4. The positive pair costs energy to assemble, but the two attractive pairs lower the total by more.
Common mix-up

Sum distinct pairs once; qV_other summed over every charge needs a factor of one half.

CHECK THE IDEA

Can the total be zero although individual pair energies are nonzero?

Compare with an explanation

Yes. Positive and negative pair contributions can cancel.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Change the sign of the third charge and compare the three pair bars. Change triangle size at fixed charges and predict how the total scales.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Three distinct pair contributionsJ · same scale for all bars0Pair 1–20.009Pair 1–3-0.009Pair 2–3-0.009

Equilateral side 1 m. Total U = -0.009 J. Each pair appears once; the first charge has zero assembly interaction work.

Sequential assembly: same final energyJ · same scale for all bars0Bring charge 20.009Bring charge 3-0.018Total U-0.009

Three held point charges on an equilateral triangle; zero interaction energy at infinite separation. Unique pair energies only, with no point-charge self-energy. Positions are fixed; this is not a motion simulation.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use the relevant potential, energy, work, field-gradient or line-integral relationship to justify your prediction.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. Four charges have how many distinct pairs?

Show answer and reasoning

6. There are 4×3/2 = 6 unique pairs.

2. Three +1 μC charges on a 1 m equilateral triangle have total U…

Show answer and reasoning

0.027 J. Three pairs each contribute +0.009 J.

Original written challenge

4 points · self-check · not an official AP question

Place +1 μC at x = 0, −1 μC at x = 1 m, and +2 μC at x = 2 m. Calculate the three pair terms and total U.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: U₁₂ = −0.009 J because r₁₂ = 1 m.
  2. 1 point: U₁₃ = +0.009 J because r₁₃ = 2 m.
  3. 1 point: U₂₃ = −0.018 J because r₂₃ = 1 m.
  4. 1 point: Total U = −0.018 J, counting each pair once.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1How many pairs for N charges?

N(N − 1)/2.

RECALL 2Does assembly order affect final electrostatic U?

No, if the final configuration and reference are the same.

RECALL 3Why omit self-energy here?

The model describes interactions between distinct point charges.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Count each charge pair exactly once

  • U = Σ_(i<j) kq_iq_j/r_ij.
  • For a complete finite configuration, U = ½Σq_iV_other,i.
  • Exclude self-potentials from V_other.

Remember: Sum distinct pairs once; qV_other summed over every charge needs a factor of one half.

Conditions: Three held point charges on an equilateral triangle; zero interaction energy at infinite separation. Unique pair energies only, with no point-charge self-energy. Positions are fixed; this is not a motion simulation.

Refresh Kid · AP Physics C: Electricity and Magnetism Unit 2 (official Unit 9) · Objectives 9.1.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 9.1, objectives 9.1.A. CED effective Fall 2024, current PDF ©2026; checked September 16, 2026. This is E&M Unit 2: Electric Potential, numbered Unit 9 in the official combined Physics C sequence. Topics 9.1–9.3 retain their official identifiers. Models assume electrostatic fields and state whether source charges are fixed or free. Potential integrals use the specified rods, ring, arc and infinite line or cylinder. Infinite-line examples use a finite reference radius, not zero potential at infinity. The optional 3D equipotential surface uses height to represent volts, not a particle trajectory. Checked with the Fall 2026 clarifications. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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