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LESSON 09 / 22 · TOPIC 1.4

Elemental analysis can test a stated purity model

You will be able to: Infer purity only after stating which component supplies the measured element.

Particles, measurements and chemical reasoningFree study resourceReview editionTeacher review pending

When can a measured element mass reveal purity?

A sample labeled calcium carbonate may contain an impurity. If only the calcium carbonate supplies calcium, measured calcium mass can tell us how much calcium carbonate is present. If the impurity also contains calcium, the same calculation no longer works.

A useful starting point: A mixture can vary while each compound keeps its formula →

Words and symbols before equations

Purity
Mass fraction of the target substance in the sample.
Tracer element
An element assigned to a known component under an explicit composition model.
Assumption check
A statement about what the impurity contains and whether the analysis accounts for all of the chosen element.
Calcium tracks target under the stated assumptionMass (g) · Ca is part of the target, not an extra component01234CaCO₃4Impurity1Ca within target1.6
Read this model snapshot. CaCO₃ 4 g; impurity 1 g; measured Ca 1.6 g (32% of sample). Inferred purity 80%.
What this picture assumes

CaCO₃ plus a calcium-free impurity; complete elemental recovery. Rounded Ca = 40, C = 12, O = 16 g/mol gives calcium fraction 0.40. An impurity containing calcium would invalidate the inverse purity calculation.

Read the picture in three steps

  1. Identify the chemical species and the quantities each label or axis represents. Read the units and any scale assumptions before comparing values.
  2. CaCO₃ 4 g; impurity 1 g; measured Ca 1.6 g (32% of sample). Inferred purity 80%.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

Use rounded molar masses Ca = 40, C = 12 and O = 16 g/mol. Pure CaCO₃ has 40 g Ca per 100 g compound: a calcium mass fraction of 0.40.

If all measured calcium comes from CaCO₃, divide calcium mass by 0.40 to infer CaCO₃ mass. Divide that by total sample mass to find purity.

A measured calcium percentage below 40% is consistent with dilution by a calcium-free impurity, but is not proof of that identity. Values above the possible limit or an unknown calcium-containing impurity invalidate this simple model.

A worked example, step by step

A 5.00 g sample yields 1.60 g Ca in complete analysis. Assume the sample is CaCO₃ plus a calcium-free impurity. Find purity.

  1. Pure CaCO₃ calcium mass fraction is 40/100 = 0.40.
  2. Inferred CaCO₃ mass = 1.60/0.40 = 4.00 g.
  3. Purity = 4.00/5.00 = 0.800, or 80.0%.
  4. The remaining 1.00 g is assigned to impurity only under the stated two-component assumption.
Common mix-up

Composition evidence alone may fit several mixtures; never infer a unique purity without a justified model.

CHECK THE IDEA

Would this work unchanged for a CaO impurity?

Compare with an explanation

No. CaO also supplies calcium, so the tracer is no longer unique to CaCO₃.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Increase the modeled purity from 0% to 100%. Predict the maximum calcium mass and explain the calcium-free impurity assumption.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Calcium tracks target under the stated assumptionMass (g) · Ca is part of the target, not an extra component01234CaCO₃4Impurity1Ca within target1.6

CaCO₃ 4 g; impurity 1 g; measured Ca 1.6 g (32% of sample). Inferred purity 80%.

CaCO₃ plus a calcium-free impurity; complete elemental recovery. Rounded Ca = 40, C = 12, O = 16 g/mol gives calcium fraction 0.40. An impurity containing calcium would invalidate the inverse purity calculation.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use particle counts, mass or charge balance, electron structure, or nuclear attraction to justify your prediction. Separate an observation from an explanation.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. A 10 g sample is 80% CaCO₃. With f(Ca)=0.40, its Ca mass is…

Show answer and reasoning

3.2 g. 10 × 0.80 × 0.40 = 3.2 g.

2. A 5 g sample contains 2.5 g Ca. Under the CaCO₃ plus Ca-free impurity model this is…

Show answer and reasoning

inconsistent with the model. Pure CaCO₃ would contain at most 2.0 g Ca. The assumptions or measurements need revision.

Original written challenge

4 points · self-check · not an official AP question

A 12.0 g sample contains 3.60 g Ca. Assume CaCO₃ plus a calcium-free impurity, with 40% Ca in pure CaCO₃. Find target mass, purity and impurity mass, and propose one reason a result could be misleading.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: CaCO₃ mass is 3.60/0.40 = 9.00 g.
  2. 1 point: Purity is 9.00/12.0 = 75.0%.
  3. 1 point: Impurity mass is 3.00 g.
  4. 1 point: An impurity containing calcium or incomplete elemental recovery would invalidate the stated inference.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What makes a tracer useful?

Its measured contribution is tied to a known component.

RECALL 2Can calculated purity exceed 100% in a valid two-component model?

No; that flags inconsistent assumptions or data.

RECALL 3Why state impurity composition?

It determines whether the measured element uniquely tracks the target.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Elemental analysis can test a stated purity model

  • m(target) = m(tracer)/f(tracer,target).
  • Purity = m(target)/m(sample).

Remember: Composition evidence alone may fit several mixtures; never infer a unique purity without a justified model.

Conditions: CaCO₃ plus a calcium-free impurity; complete elemental recovery. Rounded Ca = 40, C = 12, O = 16 g/mol gives calcium fraction 0.40. An impurity containing calcium would invalidate the inverse purity calculation.

Refresh Kid · AP Chemistry Unit 1 · Objectives 1.4.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 1.4, objectives 1.4.A. CED effective Fall 2024, current official file checked September 16, 2026, together with the published clarifications. This is Unit 1: Atomic Structure and Properties, Topics 1.1–1.8. The topic mapping identifies a framework area; focused lesson titles are our own teaching sequence. Molecular-formula scaling is an application of empirical composition. Models explicitly distinguish atom counts, molecule counts, mass fractions and electron structure. Spectra marked schematic are not measured data. Mass spectra here use single-element, singly charged monatomic ions. Configurations avoid Aufbau exceptions and individual quantum-number assignments. Qualitative attraction and size indices are not exact atomic predictions. The optional NaCl-type spatial block supplements complete charge-balance explanations. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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