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LESSON 03 / 22 · TOPIC 1.2

Read isotope identity and abundance from a mass spectrum

You will be able to: Distinguish isotope mass from relative abundance in a simple elemental mass spectrum.

Particles, measurements and chemical reasoningFree study resourceReview editionTeacher review pending

What do the positions and sizes of isotope peaks tell us?

Imagine sorting a bag of tokens by mass, then counting how many tokens enter each group. A simple elemental mass spectrum separates the mass information from the count information in a similar way.

A useful starting point: A chemical formula connects molecules to atoms →

Words and symbols before equations

Isotope
Atoms with the same proton count but different neutron counts.
Protons and neutrons
Nuclear particles: protons carry positive charge and define the element; neutrons have no electric charge and change the isotope mass.
m/z
Mass-to-charge ratio; for the singly charged monatomic ions here, the numerical position corresponds to isotope mass in u.
Relative abundance
Fraction of the element’s atoms belonging to an isotope, not its mass fraction.
Two isotope peaks at fixed mass positionsNormalized abundance (%) · singly charged ions025507510010 u3011 u70
Read this model snapshot. 10 u isotope: 30%; 11 u isotope: 70%. Mass positions stay fixed as abundance changes.
What this picture assumes

Fictional two-isotope sample, masses 10 and 11 u. Singly charged monatomic ions, normalized signals; no molecular fragments. Peak position and abundance are independent encodings.

Read the picture in three steps

  1. Identify the chemical species and the quantities each label or axis represents. Read the units and any scale assumptions before comparing values.
  2. 10 u isotope: 30%; 11 u isotope: 70%. Mass positions stay fixed as abundance changes.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

An isotope peak appears at a position related to that isotope’s mass. Its signal represents how abundant that isotope is under the simplified assumptions stated here.

A taller peak does not mean a heavier isotope. Read horizontal position for mass and the vertical scale for abundance. If the instrument reports relative intensities, divide each signal by the sum before treating it as a fraction.

We use only one element and singly charged monatomic ions. Molecular fragments and multiply charged peaks require additional interpretation and are outside this lesson’s model. The adjustable 10 u and 11 u peaks are a fictional two-isotope teaching sample, not natural abundance data.

Read two different axes
PropertyPeak positionRelative peak signal
MeaningMass-to-charge ratioIsotope abundance in this simplified model
QuestionWhich isotope?What fraction of the atoms?
Keep distinctNot electron binding energyNot the mass fraction

A worked example, step by step

Two singly charged isotope peaks have masses 10 u and 11 u and signals 30 and 70. Find their percent abundances.

  1. Add signal values: 30 + 70 = 100.
  2. The 10 u isotope fraction is 30/100 = 0.30, or 30%.
  3. The 11 u isotope fraction is 70/100 = 0.70, or 70%.
  4. The heavier isotope is more common in this sample; the two pieces of evidence come from different axes.
Common mix-up

Peak height describes abundance, not the mass of an individual isotope.

CHECK THE IDEA

If both signals double, do the isotope fractions change?

Compare with an explanation

No. Their ratios to the total remain the same.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Change the percentage of the lighter isotope. Explain why peak heights change while peak positions stay fixed.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Two isotope peaks at fixed mass positionsNormalized abundance (%) · singly charged ions025507510010 u3011 u70

10 u isotope: 30%; 11 u isotope: 70%. Mass positions stay fixed as abundance changes.

Fictional two-isotope sample, masses 10 and 11 u. Singly charged monatomic ions, normalized signals; no molecular fragments. Peak position and abundance are independent encodings.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use particle counts, mass or charge balance, electron structure, or nuclear attraction to justify your prediction. Separate an observation from an explanation.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. A peak farther right on this increasing m/z axis indicates…

Show answer and reasoning

a heavier singly charged isotope. Under the stated single-charge assumption, the position tracks isotope mass.

2. Signals of 20 and 60 correspond to a lighter-isotope abundance of…

Show answer and reasoning

25%. 20/(20+60) = 0.25.

Original written challenge

4 points · self-check · not an official AP question

A fictional element has singly charged peaks at 40 u and 42 u with signals 15 and 45. Determine both abundances and explain whether these must be two elements.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: Total signal is 60.
  2. 1 point: The 40 u isotope fraction is 15/60 = 25%.
  3. 1 point: The 42 u isotope fraction is 45/60 = 75%.
  4. 1 point: They can be isotopes of the same element: same proton count and different neutron counts.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What identifies isotope mass?

Horizontal peak position with the charge assumption stated.

RECALL 2What identifies isotope abundance?

Relative signal normalized to the total.

RECALL 3What changes between isotopes of one element?

Neutron count; proton count stays fixed.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Read isotope identity and abundance from a mass spectrum

  • fᵢ = signalᵢ / Σsignal.
  • Σfᵢ = 1.
  • For z = +1, peak position identifies isotope mass numerically.

Remember: Peak height describes abundance, not the mass of an individual isotope.

Conditions: Fictional two-isotope sample, masses 10 and 11 u. Singly charged monatomic ions, normalized signals; no molecular fragments. Peak position and abundance are independent encodings.

Refresh Kid · AP Chemistry Unit 1 · Objectives 1.2.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 1.2, objectives 1.2.A. CED effective Fall 2024, current official file checked September 16, 2026, together with the published clarifications. This is Unit 1: Atomic Structure and Properties, Topics 1.1–1.8. The topic mapping identifies a framework area; focused lesson titles are our own teaching sequence. Molecular-formula scaling is an application of empirical composition. Models explicitly distinguish atom counts, molecule counts, mass fractions and electron structure. Spectra marked schematic are not measured data. Mass spectra here use single-element, singly charged monatomic ions. Configurations avoid Aufbau exceptions and individual quantum-number assignments. Qualitative attraction and size indices are not exact atomic predictions. The optional NaCl-type spatial block supplements complete charge-balance explanations. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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