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LESSON 08 / 22 · TOPIC 6.4

Why is reaction heat opposite to the solution’s heat?

You will be able to: Calculate reaction heat from solution and calorimeter temperature changes.

Particles, measurements and chemical reasoningFree study resourceReview editionTeacher review pending

Why is reaction heat opposite to the solution’s heat?

A solution warms after two reagents mix in an insulated cup. The thermometer measures the liquid’s warming; the chemical transformation supplied that energy.

A useful starting point: How can cooling a metal reveal its specific heat? →

Words and symbols before equations

q_solution
Heat assigned to warming or cooling the solution.
Calorimeter constant, Ccal
Heat capacity of cup, probe and included apparatus; J/K.
q_reaction
Heat of the reacting process, opposite to accounted surroundings heat.
Constant pressure
Condition under which reaction heat gives enthalpy change with only pressure–volume work.
Measured warming/cooling → reaction heatMeasured warming/cooling → reaction heatq_solution=100×4.00×(5)=2000 Jq_cal=20×(5)=100 Jq_rxn=−(q_solution+q_cal)=-2100 JPer 0.050 mol reaction: ΔrH=-42 kJ/mol
Read this model snapshot. Reaction q=-2.1 kJ; molar ΔrH=-42 kJ/mol. Solution and cup warm while reaction releases heat.
What this picture assumes

100 g solution, c=4.00 J/(g·K), 0.050 mol of a 1:1 reaction. Solution and cup start and finish at common temperatures. Negligible external exchange; q_rxn=−(mc+Ccal)ΔT.

Read the picture in three steps

  1. Read the species and labels first. Identify what each symbol and line represents. Read the units and fixed conditions before comparing quantities.
  2. Reaction q=-2.1 kJ; molar ΔrH=-42 kJ/mol. Solution and cup warm while reaction releases heat.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

Use q_solution=m_solution c_solution ΔT, taking the mass of all solution that changes temperature, not only one reagent.

If apparatus heat capacity matters and it follows the same ΔT, q_cal=CcalΔT. Then q_reaction=−(q_solution+q_cal) when external heat exchange is negligible.

A positive solution ΔT gives negative reaction heat in this model. For molar reaction enthalpy, divide by the moles reacted using the balanced-equation convention.

State any water-like density or specific-heat approximation. Mix reagents at the same initial temperature, stir, and collect temperatures promptly; otherwise the simple single-ΔT balance may fail.

A worked example, step by step

100 g solution with c=4.00 J/(g·K) warms by 5.0 K. Ccal=20 J/K. Exactly 0.050 mol of a 1:1 reaction occurs. Find q_reaction and molar ΔH.

  1. q_solution=100×4.00×5.0=2000 J.
  2. q_cal=20×5.0=100 J.
  3. q_reaction=−2100 J=−2.10 kJ.
  4. ΔH per mole reacted=−2.10/0.050=−42 kJ/mol; include both receiving parts before applying the minus sign.
Common mix-up

The thermometer’s positive ΔT is not a positive reaction ΔH. Distinguish chemical energy release from solution warming.

CHECK THE IDEA

If the cup absorbs heat too, should it be omitted?

Compare with an explanation

Only if its heat capacity is negligible by an explicit approximation. Otherwise include it.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Change ΔT and then Ccal. Compare heat received by solution and apparatus with reaction heat; include an endothermic cooling case.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Measured warming/cooling → reaction heatMeasured warming/cooling → reaction heatq_solution=100×4.00×(5)=2000 Jq_cal=20×(5)=100 Jq_rxn=−(q_solution+q_cal)=-2100 JPer 0.050 mol reaction: ΔrH=-42 kJ/mol

Reaction q=-2.1 kJ; molar ΔrH=-42 kJ/mol. Solution and cup warm while reaction releases heat.

100 g solution, c=4.00 J/(g·K), 0.050 mol of a 1:1 reaction. Solution and cup start and finish at common temperatures. Negligible external exchange; q_rxn=−(mc+Ccal)ΔT.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using heat-flow signs, energy conservation, phase changes, bond inventories or the stated thermochemical path. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. 80 g solution, c=4.0, ΔT=−2.0 K and negligible cup gives q_rxn…

Show answer and reasoning

+640 J. Solution loses 640 J, so the process absorbs 640 J.

2. Which mass belongs in q_solution?

Show answer and reasoning

Total solution mass that changes temperature. The heat capacity describes the entire warmed/cooled solution.

Original written challenge

4 points · self-check · not an official AP question

120 g solution with c=4.0 J/(g·K), Ccal=40 J/K and ΔT=3.0 K records 0.040 mol reaction. Calculate both surroundings heats, q_rxn and molar ΔH.

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Compare with the answer and four-point rubric
  1. 1 point: q_solution=120×4.0×3.0=1440 J.
  2. 1 point: q_cal=40×3.0=120 J.
  3. 1 point: q_rxn=−1560 J=−1.56 kJ.
  4. 1 point: ΔH=−1.56/0.040=−39 kJ/mol for the stated reaction amount.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1Why a minus sign for q_rxn?

The measured receiving bodies gain what the reaction releases, or vice versa.

RECALL 2When include Ccal?

When apparatus heat capacity is non-negligible.

RECALL 3What mass is needed?

The mass of the solution whose temperature changes.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Why is reaction heat opposite to the solution’s heat?

  • q_rxn=−(mc+Ccal)ΔT for the stated insulated coffee-cup model.
  • Convert J to kJ before dividing by moles for kJ/mol.

Remember: The thermometer’s positive ΔT is not a positive reaction ΔH. Distinguish chemical energy release from solution warming.

Conditions: 100 g solution, c=4.00 J/(g·K), 0.050 mol of a 1:1 reaction. Solution and cup start and finish at common temperatures. Negligible external exchange; q_rxn=−(mc+Ccal)ΔT.

Refresh Kid · AP Chemistry Unit 6 · Objectives 6.4.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 6.4, objective 6.4.A. CED effective Fall 2024 and June 2026 clarifications checked September 16, 2026. Unit 6: Thermochemistry, Topics 6.1–6.9. Focused lesson names, examples, models and assessments are original Refresh Kid teaching materials, not additional official topics or official AP questions. Official corrections.

The model states its assumptions beside the diagram. Technical enthalpy/internal-energy distinctions and formal state-function terminology are not assessed in the current AP framework. Constant-pressure heat, conservation, phase-specific capacities, reaction amounts and Hess sums are taught here with explicit conditions. Supplied rounded data and original molecular geometry are teaching models, not experimental measurements. A phase transition preserves molecular identity; a bond-energy accounting path is not an actual reaction mechanism.

Teaching resources: The Organic Chemistry Tutor video titles/descriptions and topic coverage were checked for optional links; no claim is made to have watched every video. No creator scripts, examples, worksheets or artwork were copied. GitHub’s 3D website collection and its Three.js camera-control example informed the idea of controllable spatial inspection. Scientific diagrams, geometry and interactions here are original. The self-hosted Three.js runtime retains its MIT license. Camera rotation changes the view, not the chemistry.

Independent teacher review and observation of students remain pending. Implementation checks do not certify scientific accuracy, accessibility or learning effectiveness. This is a review edition.

Optional official resource: Released AP Chemistry questions and scoring guides. This archive contains questions across units; it is not an assignment of every question to this lesson.

The teaching sequence is informed by the IES learning guide; this exact implementation has not been evaluated with learners.

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