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LESSON 10 / 22 · TOPIC 6.5

Where does heat go while a substance melts?

You will be able to: Calculate phase-transition heat and distinguish changing interactions from changing temperature.

Particles, measurements and chemical reasoningFree study resourceReview editionTeacher review pending

Where does heat go while a substance melts?

Ice can keep melting while the mixture stays at its melting temperature. Energy still enters, but it changes the arrangement and interactions rather than producing a temperature rise during the ideal phase transition.

A useful starting point: How does heat escaping change a calorimetry result? →

Words and symbols before equations

Phase transition
Change between solid, liquid and gas.
Molar enthalpy of fusion, ΔHfus
Heat per mole to melt at the stated transition conditions.
Molar enthalpy of vaporization, ΔHvap
Heat per mole to vaporize at the stated conditions.
Coexisting phases
Two phases present together during a transition.
Transition heat: temperature can stay constantTransition heat: temperature can stay constantMelting; amount transformed 0.25 molSupplied signed transition enthalpy: 6 kJ/molq=nΔH=1.5 kJPure sample; fixed-pressure transition coexistence.
Read this model snapshot. Melting: q=1.5 kJ for 0.25 mol. During ideal coexistence T stays fixed. The separate liquid molecular view keeps all eight H₂O molecules intact; it is not tied to sample moles or the selected heat calculation.
What this picture assumes

Heat uses supplied rounded ΔHfus=6.00 and ΔHvap=40.0 kJ/mol at their respective transition conditions; fixed pressure, pure phase coexistence. Separate molecular-water selector compares liquid/vapor geometry only: eight intact H₂O markers, fixed count independent of moles, arbitrary spacing/orientation, not actual density or trajectories.

Read the picture in three steps

  1. Read the species and labels first. Identify what each symbol and line represents. Read the units and fixed conditions before comparing quantities.
  2. Melting: q=1.5 kJ for 0.25 mol. During ideal coexistence T stays fixed. The separate liquid molecular view keeps all eight H₂O molecules intact; it is not tied to sample moles or the selected heat calculation.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

At fixed pressure, a pure substance undergoing an equilibrium phase transition remains at its transition temperature while both phases coexist.

Melting and vaporization absorb energy; freezing and condensation release it. Reverse transitions at the same conditions have equal magnitudes and opposite signs.

Use q=nΔH_transition with the supplied molar enthalpy and amount actually transformed. A zero ΔT does not imply q=0 during a phase change.

In vaporizing molecular water, H₂O molecules remain intact; the main separation is between molecules. The optional spatial model highlights this distinction without treating the drawing as a real density or trajectory.

A worked example, step by step

At its melting point, 0.250 mol of a supplied pure substance melts with ΔHfus=6.00 kJ/mol. Find q and the reverse-process heat.

  1. Use amount in moles because the enthalpy is per mole.
  2. q_melt=0.250×6.00=+1.50 kJ.
  3. Freezing the same amount at the same conditions gives −1.50 kJ.
  4. Temperature stays at the transition value during the ideal two-phase process; heat changes phase rather than temperature.
Common mix-up

Do not use q=mcΔT alone during a constant-temperature phase transition. Its ΔT term does not include latent energy.

CHECK THE IDEA

Does boiling water normally break its O–H covalent bonds?

Compare with an explanation

No. Water molecules separate while remaining H₂O; boiling is not decomposition into H and O atoms.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Choose melting/freezing or vaporization/condensation and change moles. Predict the sign and linear amount dependence before reading the result.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Transition heat: temperature can stay constantTransition heat: temperature can stay constantMelting; amount transformed 0.25 molSupplied signed transition enthalpy: 6 kJ/molq=nΔH=1.5 kJPure sample; fixed-pressure transition coexistence.

Melting: q=1.5 kJ for 0.25 mol. During ideal coexistence T stays fixed. The separate liquid molecular view keeps all eight H₂O molecules intact; it is not tied to sample moles or the selected heat calculation.

Liquid snapshot: eight intact H₂O molecules; arbitrary spacingLiquid snapshot: eight intact H₂O molecules; arbitrary spacingOHHOHHOHHOHHOHHOHHOHHOHHSchematic oblique view; rotate optional 3D to inspect hidden bonds.

Heat uses supplied rounded ΔHfus=6.00 and ΔHvap=40.0 kJ/mol at their respective transition conditions; fixed pressure, pure phase coexistence. Separate molecular-water selector compares liquid/vapor geometry only: eight intact H₂O markers, fixed count independent of moles, arbitrary spacing/orientation, not actual density or trajectories.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using heat-flow signs, energy conservation, phase changes, bond inventories or the stated thermochemical path. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. 0.50 mol condenses with ΔHvap=40 kJ/mol at the same conditions. q?

Show answer and reasoning

−20 kJ. Condensation reverses vaporization: 0.50×(−40)=−20 kJ.

2. During an ideal melting plateau, added energy primarily…

Show answer and reasoning

Changes phase and interparticle interactions. At fixed pressure and phase coexistence, temperature stays constant while the phase fraction changes.

Original written challenge

4 points · self-check · not an official AP question

A 0.40 mol sample freezes at its transition temperature with ΔHfus=7.5 kJ/mol. Calculate q, state the surroundings sign and temperature behavior, and explain why mcΔT alone is insufficient.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: q_freeze=0.40(−7.5)=−3.0 kJ.
  2. 1 point: The receiving surroundings gain +3.0 kJ if other exchanges are absent.
  3. 1 point: The sample stays at its freezing temperature during ideal coexistence.
  4. 1 point: mcΔT alone omits the enthalpy of changing phase.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What controls transition heat amount?

Moles transformed and the molar transition enthalpy.

RECALL 2What happens to temperature during ideal coexistence?

It stays at the transition temperature at fixed pressure.

RECALL 3What reverses on freezing instead of melting?

The sign of the phase-change heat.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Where does heat go while a substance melts?

  • q=nΔH_transition at the specified phase-transition conditions.
  • Reverse transition: same magnitude, opposite sign.

Remember: Do not use q=mcΔT alone during a constant-temperature phase transition. Its ΔT term does not include latent energy.

Conditions: Heat uses supplied rounded ΔHfus=6.00 and ΔHvap=40.0 kJ/mol at their respective transition conditions; fixed pressure, pure phase coexistence. Separate molecular-water selector compares liquid/vapor geometry only: eight intact H₂O markers, fixed count independent of moles, arbitrary spacing/orientation, not actual density or trajectories.

Refresh Kid · AP Chemistry Unit 6 · Objectives 6.5.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 6.5, objective 6.5.A. CED effective Fall 2024 and June 2026 clarifications checked September 16, 2026. Unit 6: Thermochemistry, Topics 6.1–6.9. Focused lesson names, examples, models and assessments are original Refresh Kid teaching materials, not additional official topics or official AP questions. Official corrections.

The model states its assumptions beside the diagram. Technical enthalpy/internal-energy distinctions and formal state-function terminology are not assessed in the current AP framework. Constant-pressure heat, conservation, phase-specific capacities, reaction amounts and Hess sums are taught here with explicit conditions. Supplied rounded data and original molecular geometry are teaching models, not experimental measurements. A phase transition preserves molecular identity; a bond-energy accounting path is not an actual reaction mechanism.

Teaching resources: The Organic Chemistry Tutor video titles/descriptions and topic coverage were checked for optional links; no claim is made to have watched every video. No creator scripts, examples, worksheets or artwork were copied. GitHub’s 3D website collection and its Three.js camera-control example informed the idea of controllable spatial inspection. Scientific diagrams, geometry and interactions here are original. The self-hosted Three.js runtime retains its MIT license. Camera rotation changes the view, not the chemistry.

Independent teacher review and observation of students remain pending. Implementation checks do not certify scientific accuracy, accessibility or learning effectiveness. This is a review edition.

Optional official resource: Released AP Chemistry questions and scoring guides. This archive contains questions across units; it is not an assignment of every question to this lesson.

The teaching sequence is informed by the IES learning guide; this exact implementation has not been evaluated with learners.

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