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LESSON 05 / 16 · TOPIC 2.4

Inertia and constant velocity

You will be able to: Distinguish zero acceleration from zero velocity in an inertial frame.

Free study resourceReview editionTeacher review pending

Does something moving right need a net force right?

Imagine a puck already sliding right on nearly frictionless ice. Once the push stops, it keeps moving. A continuing push is needed to overcome resistance in everyday life, not to sustain motion itself.

A useful starting point: Acceleration and signs →

Words and symbols before equations

Inertia
Resistance to changes in velocity; greater mass means greater inertia.
Equilibrium
Zero net force; here, translational equilibrium.
Inertial frame
A nonaccelerating reference frame where Newton’s first law holds.
Forces ON the object · +x right, +y up2 kgPush 8 N →Resistance 3 N ←Normal 20 N ↑Weight 20 N ↓
Read this model snapshot. Net horizontal force 5 N; acceleration 2.5 m/s² (right positive). Force arrows share a scale of 4.75 drawing units/N.
What this picture assumes

Horizontal net-force investigation: right is positive. Resistance is a prescribed force, not a static-friction solver. Vertical support balances weight; g=10 m/s². Velocity is not specified.

Connect the picture to the physics

When external forces sum to zero, velocity stays constant. Constant velocity includes rest but also straight-line motion at a steady speed.

A puck sliding at 3 m/s right can have zero horizontal force. If a 2 N pull right balances 2 N resistance left, it also has zero horizontal net force. Different force lists can produce the same acceleration.

In a bus that brakes, an unrestrained object seems to move forward relative to the bus. From the road’s approximately inertial frame it tends to keep its previous velocity. Do not invent a real forward interaction merely to explain the bus-frame appearance.

A worked example, step by step

A box moves right at 2 m/s. A rope pulls 6 N right while friction acts 6 N left. Its mass is 3 kg. Describe the next 4 s if these forces stay constant.

  1. Take right positive: horizontal net force is 6−6 = 0 N.
  2. Zero net force gives zero acceleration. The box keeps velocity +2 m/s.
  3. In 4 s its displacement is 2×4 = +8 m.
  4. Zero net force did not stop the box; it prevented any velocity change.
Common mix-up

Zero net force does not mean no individual forces, and it does not mean zero velocity.

CHECK THE IDEA

Can a car turning at constant speed have zero net force?

Compare with an explanation

No. Its velocity direction changes, so it accelerates.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Set applied force equal to resistance. Keep mass fixed. Read the zero acceleration and explain both a stationary and a moving situation consistent with that result.

Forces ON the object · +x right, +y up2 kgPush 8 N →Resistance 3 N ←Normal 20 N ↑Weight 20 N ↓

Net horizontal force 5 N; acceleration 2.5 m/s² (right positive). Force arrows share a scale of 4.75 drawing units/N.

Acceleration (m/s²)Applied force (N)0-105-2.51051512.52020

Horizontal net-force investigation: right is positive. Resistance is a prescribed force, not a static-friction solver. Vertical support balances weight; g=10 m/s². Velocity is not specified.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use a force or motion relationship to justify your prediction.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. A moving object has zero net force. It will…

Show answer and reasoning

Keep constant velocity. No net force means no change in velocity.

2. Which frame is approximately inertial?

Show answer and reasoning

A steadily moving straight train. Constant straight-line velocity gives no frame acceleration.

Original written challenge

4 points · self-check · not an official AP question

A cart travels left at 4 m/s while two horizontal forces of 5 N oppose each other. (a) Find net force, (b) give acceleration, (c) find displacement in 3 s with right positive, and (d) describe the velocity-time graph.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: 0 N.
  2. 1 point: 0 m/s².
  3. 1 point: −12 m.
  4. 1 point: A horizontal line at −4 m/s; its zero slope represents zero acceleration.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1Does equilibrium require rest?

No; constant straight-line velocity is also possible.

RECALL 2What does inertia resist?

Changes in velocity, not motion itself.

RECALL 3Why distinguish reference frames?

A frame accelerating relative to an inertial frame changes how motion appears.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Inertia and constant velocity

  • ΣF = 0 → a = 0 → constant velocity in an inertial frame.
  • For constant velocity, Δx = vΔt.

Remember: Zero net force does not mean no individual forces, and it does not mean zero velocity.

Conditions: Horizontal net-force investigation: right is positive. Resistance is a prescribed force, not a static-friction solver. Vertical support balances weight; g=10 m/s². Velocity is not specified.

Refresh Kid · Unit 2 · Objectives 2.4.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 2.4, objectives 2.4.A. CED effective Fall 2024, current PDF ©2026; checked September 16, 2026. Fall-2026 corrections also checked. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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