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LESSON 08 / 14 · TOPIC 8.3

Floating is a force balance, not a size contest

You will be able to: Use average density and displaced volume to explain floating, sinking and neutral buoyancy.

Free study resourceReview editionTeacher review pending

Why can a large boat float while a small stone sinks?

A boat’s hull excludes a large volume of water while enclosing relatively little total mass for that volume. It can displace its own weight of water before fully submerging. A compact stone usually cannot do that before all of its volume is underwater.

A useful starting point: Buoyancy comes from unequal pressure forces →

Words and symbols before equations

Average object density ρ_o
Total object mass divided by the overall volume that can exclude fluid.
Floating equilibrium
At rest at the surface with B=mg and no other vertical support.
Submerged fraction
V_disp/V_object, a dimensionless ratio.
Neutral buoyancy
For a fully submerged object, buoyancy balances weight in the ideal model.
Floating equilibriumB=12 NW=12 NSubmerged: 60% · force arrows: 3 units/N
Read this model snapshot. Object density=600 kg/m³; mass=1.2 kg. Floating equilibrium. Submerged volume=0.0012 m³; B=12 N, weight=12 N; net upward force=0 N.
What this picture assumes

Rigid object volume 0.002 m³, water density 1000 kg/m³, g=10 m/s². No surface tension or other support. Lower-density cases show surface equilibrium; equal density shows neutral full immersion; denser cases show an initially stationary fully submerged release. Geometry is schematic.

Connect the picture to the physics

For floating equilibrium, ρ_f gV_disp=mg=ρ_o gV_object. Cancel g to get V_disp/V_object=ρ_o/ρ_f. A 600 kg/m³ object floating in 1000 kg/m³ water has 60% of its volume submerged.

The required fraction cannot exceed 1. If ρ_o>ρ_f, full submersion still gives B<mg, so an initially stationary unsupported object accelerates downward. If densities match, it can remain fully submerged with B=mg. This does not mean every moving object instantly stops; net force determines acceleration.

For a hollow object, use total mass and the volume actually excluding fluid. If a hull floods, its effective displacement and average-density accounting change. Surface tension and trapped-air changes are outside this simple model. Size or mass alone cannot decide whether an object floats.

Initially at rest, fully submerged and released
Average object densityBuoyancy vs weightInitial response
Less than fluidB>mgAccelerates upward
Equal to fluidB=mgNeutral equilibrium in this ideal model
Greater than fluidB<mgAccelerates downward

A worked example, step by step

A uniform 0.002 m³ block has density 600 kg/m³ and floats in water at 1000 kg/m³. Use g=10 m/s². Find its mass, submerged volume and buoyant force.

  1. m=ρ_oV=600(0.002)=1.2 kg.
  2. Floating requires B=mg=12 N.
  3. V_disp=m/ρ_f=1.2/1000=0.0012 m³.
  4. The submerged fraction is 0.0012/0.002=0.60, or 60%.
Common mix-up

A floating object has B=mg, not B>mg. A net upward force would accelerate it instead of maintaining equilibrium.

CHECK THE IDEA

Does an object floating at rest need buoyancy greater than its weight?

Compare with an explanation

No. Equal forces give zero vertical acceleration; greater buoyancy would accelerate it upward.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Change object density while holding its overall volume and water density fixed. Below water density, inspect the equilibrium submerged fraction. Above water density, the model switches to a fully submerged release with a downward net force.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Floating equilibriumB=12 NW=12 NSubmerged: 60% · force arrows: 3 units/N

Object density=600 kg/m³; mass=1.2 kg. Floating equilibrium. Submerged volume=0.0012 m³; B=12 N, weight=12 N; net upward force=0 N.

Rigid object volume 0.002 m³, water density 1000 kg/m³, g=10 m/s². No surface tension or other support. Lower-density cases show surface equilibrium; equal density shows neutral full immersion; denser cases show an initially stationary fully submerged release. Geometry is schematic.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use the relevant force, motion or energy relationship to justify your prediction.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. A 750 kg/m³ object floats in 1000 kg/m³ water with submerged fraction…

Show answer and reasoning

0.75. The fraction is ρ_o/ρ_f=0.75.

2. A fully submerged object has average density greater than the liquid and is released from rest. It initially…

Show answer and reasoning

Accelerates down. Its weight exceeds the maximum buoyant force for that volume.

Original written challenge

4 points · self-check · not an official AP question

A block has volume 0.004 m³ and density 500 kg/m³. It floats in water at 1000 kg/m³; g=10 m/s². (a) Find mass. (b) Find submerged volume. (c) Find B. (d) Explain whether a second same-material block of twice the volume has a different submerged fraction.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: 2 kg.
  2. 1 point: 0.002 m³.
  3. 1 point: 20 N upward, balancing its weight.
  4. 1 point: Same fraction, 0.5: both mass and volume double, so average density is unchanged.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1Floating force balance?

B=mg when no other vertical force acts.

RECALL 2What determines submerged fraction?

Object average density divided by fluid density.

RECALL 3Does the formula predict a possible floating state when the fraction exceeds 1?

No. That object cannot float in this simple unsupported model.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

Floating is a force balance, not a size contest

  • Floating with no other support: B=mg.
  • V_disp/V_object=ρ_o/ρ_f when the ratio is at most 1.

Remember: A floating object has B=mg, not B>mg. A net upward force would accelerate it instead of maintaining equilibrium.

Conditions: Rigid object volume 0.002 m³, water density 1000 kg/m³, g=10 m/s². No surface tension or other support. Lower-density cases show surface equilibrium; equal density shows neutral full immersion; denser cases show an initially stationary fully submerged release. Geometry is schematic.

Refresh Kid · Unit 8 · Objectives 8.3.B · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 8.3, objectives 8.3.B. CED effective Fall 2024, current PDF ©2026; checked September 16, 2026. Fall-2026 corrections also checked. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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