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LESSON 04 / 20 · TOPIC 2.2

How do single, double and triple bonds compare?

You will be able to: Rank comparable bonds by order, length and energy, while stating the comparison limits.

Bonding, geometry and chemical reasoningFree study resourceReview editionTeacher review pending

How do single, double and triple bonds compare?

Two carbon atoms can share one, two or three electron pairs. Compare C–C, C=C and C≡C: the number of shared pairs helps explain why their typical lengths differ.

A useful starting point: Why is there a preferred distance between bonded atoms? →

Words and symbols before equations

Bond order
Number of bonding pairs in a localized Lewis description.
Bond length
Equilibrium separation of the nuclei, usually pm.
Bond energy
Energy needed to separate bonded atoms, often tabulated as a gas-phase average in kJ/mol.
Same atom pair: carbon–carbonCCOrder 1; example length 154 pm; example energy 350 kJ/molStick lengths are schematic; use the numerical labels.
Read this model snapshot. Order 1: 154 pm, 350 kJ/mol in this illustrative comparison. Higher order is shorter and stronger for this atom pair.
What this picture assumes

Illustrative rounded carbon–carbon comparisons, not a universal measured bond table. Atom pair is held fixed; actual values depend on environment.

Read the picture in three steps

  1. Read the species and labels first. A Lewis line represents two electrons; a spatial stick indicates connectivity. Use the stated quantities and units for numerical comparisons.
  2. Order 1: 154 pm, 350 kJ/mol in this illustrative comparison. Higher order is shorter and stronger for this atom pair.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

A single bond has order 1, a double order 2, and a triple order 3. For the same bonded elements in comparable environments, higher order generally means a shorter, stronger bond.

Do not extend that rule blindly across different elements. Atomic size matters: a single bond involving a larger atom can be longer even if its bond order is unchanged.

A double bond is not exactly twice as strong as a single bond. Tables often contain averages across several compounds, and their values depend on the chemical environment.

A worked example, step by step

Illustrative C–C values are 154 pm and 350 kJ/mol, C=C 134 pm and 610 kJ/mol, C≡C 120 pm and 840 kJ/mol. Rank them.

  1. Hold the bonded elements fixed: carbon and carbon.
  2. Increasing order from 1 to 3 decreases length: 154 > 134 > 120 pm.
  3. It increases dissociation energy: 350 < 610 < 840 kJ/mol.
  4. 610 is not 2 × 350. The illustration supports a trend, not a proportionality law.
Common mix-up

Compare like atom pairs; bond order alone cannot rank every bond in chemistry.

CHECK THE IDEA

Must a double bond be exactly twice as strong as a single bond?

Compare with an explanation

No. Its additional interaction is not a duplicate of the first, and bond energies are environment-dependent.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Choose order 1, 2 and 3 for the same carbon pair. Track how distance and the illustrative dissociation energy change together.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

Same atom pair: carbon–carbonCCOrder 1; example length 154 pm; example energy 350 kJ/molStick lengths are schematic; use the numerical labels.

Order 1: 154 pm, 350 kJ/mol in this illustrative comparison. Higher order is shorter and stronger for this atom pair.

Illustrative rounded carbon–carbon comparisons, not a universal measured bond table. Atom pair is held fixed; actual values depend on environment.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using electron accounting, electrostatic interactions or spatial geometry. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. For comparable C–C bonds, which is usually shortest?

Show answer and reasoning

Triple. Higher bond order generally pulls this same atom pair closer; atom identities must be held comparable.

2. Can the order alone prove H–F is longer than C=C?

Show answer and reasoning

No, the atom sizes and identities also differ. Order is not enough across unlike atom pairs, and there is no universal double-bond length.

Original written challenge

4 points · self-check · not an official AP question

A table gives X–X: 160 pm, 200 kJ/mol; X=X: 140 pm, 330 kJ/mol. Rank order, length and strength; evaluate the claim that double means twice the energy.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: X=X has higher order, 2 rather than 1.
  2. 1 point: X=X is shorter: 140 versus 160 pm.
  3. 1 point: X=X needs more energy to break: 330 versus 200 kJ/mol.
  4. 1 point: 330 ≠ 400, so the given data disprove exact doubling.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What does bond order count in a localized Lewis picture?

Shared electron pairs.

RECALL 2What must be comparable when using the order trend?

Atom identities and chemical environments.

RECALL 3Why are tabulated average energies approximate?

The same bond type occurs in different chemical environments.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

How do single, double and triple bonds compare?

  • For comparable atom pairs: higher order → usually shorter and stronger.
  • Average bond energies are environment-dependent.

Remember: Compare like atom pairs; bond order alone cannot rank every bond in chemistry.

Conditions: Illustrative rounded carbon–carbon comparisons, not a universal measured bond table. Atom pair is held fixed; actual values depend on environment.

Refresh Kid · AP Chemistry Unit 2 · Objectives 2.2.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 2.2, objectives 2.2.A. CED effective Fall 2024, current official file checked September 16, 2026, together with the published clarifications. This is Unit 2: Compound Structure and Properties, Topics 2.1–2.7. The focused lesson breakdown is Refresh Kid’s editorial sequence. Models and original practice are teaching materials, not official AP questions. Numerical potential curves, ion comparisons and orbital-alignment indices state their approximations. Five- and six-domain shapes are included; d-orbital hybridization and molecular-orbital diagrams are not required here. GitHub’s 3D website examples, including the Three.js Mars camera-control example, informed the use of rotatable scenes. Our scientific geometry and viewer code are original; no repository artwork or tutorial code was copied. The self-hosted Three.js library retains its MIT license. Camera rotation does not alter chemistry. See also the official clarifications.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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