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LESSON 13 / 20 · TOPIC 2.6

How does formal charge check a Lewis diagram?

You will be able to: Calculate formal charges and verify their sum against the species charge.

Bonding, geometry and chemical reasoningFree study resourceReview editionTeacher review pending

How does formal charge check a Lewis diagram?

When two people share an item equally in an account book, each receives half its value. Formal charge uses equal sharing of bonding electrons as a bookkeeping convention, even when a real bond is polar.

A useful starting point: When is an octet only a useful starting rule? →

Words and symbols before equations

Formal charge FC
Valence count minus electrons assigned by equal sharing.
Nonbonding electrons N
Electrons drawn on one atom, including lone-pair electrons.
Bonding electrons B
Electrons in all bonds connected to the atom.
Valence count V
Electrons supplied by the neutral isolated atom’s outer shell.
O in H₂OV = 6; N = 4; B = 4Assigned electrons = 4 + 4/2 = 6FC = 6 − 4 − 4/2 = 0Electron counts; formal charge is not measured partial charge.
Read this model snapshot. O in H₂O: formal charge 0. N counts nonbonding electrons, not lone pairs.
What this picture assumes

Formal charge uses equal sharing, not measured electron density. V, N and B are counts of valence, nonbonding and bonding electrons, respectively.

Read the picture in three steps

  1. Read the species and labels first. A Lewis line represents two electrons; a spatial stick indicates connectivity. Use the stated quantities and units for numerical comparisons.
  2. O in H₂O: formal charge 0. N counts nonbonding electrons, not lone pairs.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

Assign an atom all of its nonbonding electrons and half of its bonding electrons. Then FC = V − N − B/2; all quantities are electron counts.

The sum of formal charges must equal the overall species charge. This is a strong consistency check, but zero formal charges alone do not prove that a diagram has correct connectivity.

For ordinary valid alternatives, small charge separation is often preferred; negative formal charge is usually better accommodated by more electronegative atoms. Apply the electron budget and appropriate shell rules first. Formal charge is not the actual partial charge.

Two different charge descriptions
PropertyFormal chargePartial charge
BasisEqual sharing bookkeepingUnequal electron density
ExampleO in H₂O has FC = 0O is δ− in each O–H bond
UseCheck Lewis accountingDiscuss bond polarity

A worked example, step by step

Find nitrogen’s formal charge in NH₄⁺, where N has four single bonds and no lone pair.

  1. For neutral nitrogen, V = 5.
  2. No nonbonding electrons gives N = 0.
  3. Four bonds contain B = 8 bonding electrons, so N is assigned 8/2 = 4.
  4. FC = 5 − 0 − 4 = +1. Each H has FC = 0; the sum matches the ion’s +1 charge.
Common mix-up

Use nonbonding electrons, not lone-pair count, in FC = V − N − B/2.

CHECK THE IDEA

Can an atom have formal charge zero and still have a partial charge?

Compare with an explanation

Yes. Formal charge assumes equal sharing, while partial charge describes actual unequal electron density.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Choose atoms in water, ammonium and nitrate. Predict each formal charge from the displayed counts; distinguish an O with one bond from an O with two.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

O in H₂OV = 6; N = 4; B = 4Assigned electrons = 4 + 4/2 = 6FC = 6 − 4 − 4/2 = 0Electron counts; formal charge is not measured partial charge.

O in H₂O: formal charge 0. N counts nonbonding electrons, not lone pairs.

Formal charge uses equal sharing, not measured electron density. V, N and B are counts of valence, nonbonding and bonding electrons, respectively.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using electron accounting, electrostatic interactions or spatial geometry. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. O with one single bond and three lone pairs has FC…

Show answer and reasoning

−1. 6 − 6 − 2/2 = −1. Three lone pairs are six nonbonding electrons.

2. The formal charges in a valid NO₃⁻ diagram must sum to…

Show answer and reasoning

−1. Formal charge is bookkeeping for the whole ion; the sum must equal −1, not the number of oxygens.

Original written challenge

4 points · self-check · not an official AP question

In one nitrate contributor, N has four bond lines and no lone pair. One O is double-bonded with two lone pairs; two O atoms are single-bonded with three lone pairs. Calculate all formal charges and the sum.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: N: 5 − 0 − 8/2 = +1.
  2. 1 point: Double-bonded O: 6 − 4 − 4/2 = 0.
  3. 1 point: Each single-bonded O: 6 − 6 − 2/2 = −1.
  4. 1 point: Total = +1 + 0 − 1 − 1 = −1.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What is the formula for formal charge?

FC = V − N − B/2, using electron counts.

RECALL 2What does the sum check?

It must reproduce the overall charge.

RECALL 3Is formal charge a measured partial charge?

No. It is an equal-sharing bookkeeping convention.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

How does formal charge check a Lewis diagram?

  • FC = V − N − B/2.
  • Sum of formal charges = net species charge.

Remember: Use nonbonding electrons, not lone-pair count, in FC = V − N − B/2.

Conditions: Formal charge uses equal sharing, not measured electron density. V, N and B are counts of valence, nonbonding and bonding electrons, respectively.

Refresh Kid · AP Chemistry Unit 2 · Objectives 2.6.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 2.6, objectives 2.6.A. CED effective Fall 2024, current official file checked September 16, 2026, together with the published clarifications. This is Unit 2: Compound Structure and Properties, Topics 2.1–2.7. The focused lesson breakdown is Refresh Kid’s editorial sequence. Models and original practice are teaching materials, not official AP questions. Numerical potential curves, ion comparisons and orbital-alignment indices state their approximations. Five- and six-domain shapes are included; d-orbital hybridization and molecular-orbital diagrams are not required here. GitHub’s 3D website examples, including the Three.js Mars camera-control example, informed the use of rotatable scenes. Our scientific geometry and viewer code are original; no repository artwork or tutorial code was copied. The self-hosted Three.js library retains its MIT license. Camera rotation does not alter chemistry. See also the official clarifications.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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