Learning
LESSON 09 / 20 · TOPIC 2.5

How many electrons belong in a Lewis diagram?

You will be able to: Calculate the total valence-electron budget for a neutral molecule or polyatomic ion.

Bonding, geometry and chemical reasoningFree study resourceReview editionTeacher review pending

How many electrons belong in a Lewis diagram?

Before dividing a budget among purchases, count what is available. Before drawing bonds and lone pairs, count the valence electrons available to the entire species.

A useful starting point: Where do added atoms fit in an alloy? →

Words and symbols before equations

Valence-electron budget
Total outer electrons to place in the diagram.
Net charge Q
Species charge in units of e; positive means electrons have been removed.
Lone pair
Two valence electrons placed on one atom rather than between two atoms.
Bonding pair
Two electrons shared between connected atoms.
H₂O · total valence-electron budgetNeutral-atom sum: 8Net charge Q: 0Budget = 8 − (0) = 8 electrons
Read this model snapshot. H₂O: 8 valence electrons. Neutral species: no charge correction.
What this picture assumes

Valence electron counts use H=1, C=4, N=5, O=6. The net ionic charge corrects the neutral-atom sum. This count does not by itself give shape.

Read the picture in three steps

  1. Read the species and labels first. A Lewis line represents two electrons; a spatial stick indicates connectivity. Use the stated quantities and units for numerical comparisons.
  2. H₂O: 8 valence electrons. Neutral species: no charge correction.
  3. Check what the picture assumes below. Use the Explore task to predict one change before moving a control.

Connect the picture to the chemistry

Add the valence counts of every atom. For the representative elements used here: H contributes 1, C 4, N 5, O 6 and F 7.

Add one electron per negative charge and subtract one per positive charge. Charge belongs to the species; it does not change the number of nuclei.

A bond line uses two electrons from the total budget. Count each drawn pair once for the entire species, even though a bonding pair counts around both connected atoms when checking their shells.

A worked example, step by step

Find the valence-electron budget of NH₄⁺.

  1. Nitrogen contributes 5 electrons.
  2. Four H atoms contribute 4 × 1 = 4; neutral-atom total is 9.
  3. Subtract one for the +1 charge: 9 − 1 = 8 electrons.
  4. Four N–H bonds use all 8 electrons, giving each H a duet and N an octet; enclose the ion in brackets with + outside.
Common mix-up

A positive ion has fewer electrons than the neutral-atom sum, not more.

CHECK THE IDEA

Does a 2− charge mean subtract two electrons?

Compare with an explanation

No. Add two electrons relative to the neutral-atom sum.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Switch among H₂O, NH₄⁺, CO₂ and NO₃⁻. Predict the electron total before reading the count and separate the charge correction from the atom contributions.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

H₂O · total valence-electron budgetNeutral-atom sum: 8Net charge Q: 0Budget = 8 − (0) = 8 electrons

H₂O: 8 valence electrons. Neutral species: no charge correction.

Valence electron counts use H=1, C=4, N=5, O=6. The net ionic charge corrects the neutral-atom sum. This count does not by itself give shape.

Explain what you noticed: Answer the investigation prompt above. State one observation and explain it using electron accounting, electrostatic interactions or spatial geometry. Identify what the representation cannot tell you.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. For OH⁻, using O=6 and H=1, the budget is…

Show answer and reasoning

8. 6 + 1 + 1 = 8; a negative charge adds an electron.

2. How many electrons do three single bonds use?

Show answer and reasoning

6. Each line is a pair, so three lines use six electrons.

Original written challenge

4 points · self-check · not an official AP question

Calculate the budget for CO₃²⁻ using C=4 and O=6. Account for three initial single bonds and the remaining electrons, then explain why the first sketch is not yet a final structure.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: Neutral-atom sum = 4 + 3(6) = 22.
  2. 1 point: Add 2 for the charge: total 24.
  3. 1 point: Three initial bonds use 6, leaving 18 for lone pairs.
  4. 1 point: After terminal octets, carbon needs a multiple bond; accounting must be followed by shell and formal-charge checks.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What is the charge correction for a cation?

Subtract its positive charge count.

RECALL 2Do shared electrons get counted twice in the total budget?

No. Count each drawn electron once in the whole diagram.

RECALL 3What is checked after the budget?

Connectivity, shell completion and formal charges.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

How many electrons belong in a Lewis diagram?

  • Budget = sum of atomic valence electrons − Q.
  • One bond line represents two electrons.

Remember: A positive ion has fewer electrons than the neutral-atom sum, not more.

Conditions: Valence electron counts use H=1, C=4, N=5, O=6. The net ionic charge corrects the neutral-atom sum. This count does not by itself give shape.

Refresh Kid · AP Chemistry Unit 2 · Objectives 2.5.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 2.5, objectives 2.5.A. CED effective Fall 2024, current official file checked September 16, 2026, together with the published clarifications. This is Unit 2: Compound Structure and Properties, Topics 2.1–2.7. The focused lesson breakdown is Refresh Kid’s editorial sequence. Models and original practice are teaching materials, not official AP questions. Numerical potential curves, ion comparisons and orbital-alignment indices state their approximations. Five- and six-domain shapes are included; d-orbital hybridization and molecular-orbital diagrams are not required here. GitHub’s 3D website examples, including the Three.js Mars camera-control example, informed the use of rotatable scenes. Our scientific geometry and viewer code are original; no repository artwork or tutorial code was copied. The self-hosted Three.js library retains its MIT license. Camera rotation does not alter chemistry. See also the official clarifications.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

OPTIONAL LIVE SUPPORT

Want to work through this with a tutor?

Bring your question about How many electrons belong in a Lewis diagram? Your explanation and answers remain free to access.

Request a chemistry tutor →Ask about this lesson on WhatsAppThe team can confirm teacher availability and next steps.