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LESSON 15 / 16 · TOPIC 6.6

An elliptical orbit: speed changes, E and L do not

You will be able to: Use angular momentum and energy conservation to compare points on an elliptical orbit.

Free study resourceReview editionTeacher review pending

Why does a satellite move fastest near its planet?

A satellite on an elongated orbit comes close to its planet, speeds through the near part, then slows as it travels farther away. Its speed changes without a rocket burn: gravitational potential energy and kinetic energy trade while total mechanical energy stays constant.

A useful starting point: Circular orbits: gravity, energy and angular momentum →

Words and symbols before equations

Periapsis and apoapsis
Nearest and farthest points from the central body.
Central force
A force along the line joining the two bodies; gravity has zero torque about the central body.
rv sinφ
The radius–velocity product that enters particle angular momentum; φ is the angle between radius and velocity.
Bound orbit
An orbit with negative total mechanical energy, for U=0 at infinity.
One ellipse: the marker moves around a fixed orbitcentral bodyTeal radius=2 m · orange velocity, speed=3 m/sGeometry: 37.5 units/m · velocity: 18 units per m/s
Read this model snapshot. r=2 m; speed=3 m/s. K=4.5 J; U=-6 J. E=-1.5 J and L=6 kg·m²/s stay constant. Position control is not elapsed time.
What this picture assumes

One scaled orbit: GM=12 m³/s², m=1 kg, closest radius 2 m, farthest radius 6 m. Central body at a focus with radius below 2 m. Control is a geometric ellipse parameter, not a uniform clock. Drawing equations are not an additional lesson prerequisite.

Connect the picture to the physics

Gravity points toward the central body, giving zero torque about that point. Therefore the satellite’s angular momentum about it stays constant in the ideal model. Gravity is also conservative, so K+U stays constant for the satellite–central-body system.

At periapsis and apoapsis, velocity is perpendicular to the radius. Thus mr_pv_p=mr_av_a. Farther away at apoapsis, speed is lower. At a general point, velocity may not be perpendicular: use L=mrv sinφ, not simply mrv.

As r increases, U=−GMm/r becomes less negative, so K decreases by the same amount. Total E and L stay constant; K and U generally do not. The central body lies at a focus of the ellipse, not its geometric center. You can explain these changes using conservation without memorizing a new ellipse-speed formula.

A worked example, step by step

In a scaled gravity model, GM=12 m³/s² and m=1 kg. An ellipse has r_p=2 m, v_p=3 m/s and r_a=6 m. Find v_a and verify energy at the two endpoints.

  1. At both endpoints v is perpendicular to r, so r_pv_p=r_av_a.
  2. v_a=(2)(3)/6=1 m/s. L=6 kg·m²/s at both points.
  3. Near: K=4.5 J and U=−12/2=−6 J, so E=−1.5 J.
  4. Far: K=0.5 J and U=−12/6=−2 J, so E=−1.5 J. The 4 J increase in U matches a 4 J decrease in K.
Common mix-up

Do not use circular-orbit speed at arbitrary points of an ellipse. Also, mrv omits a needed sine factor away from perpendicular velocity.

CHECK THE IDEA

Is gravitational potential energy constant in an ellipse?

Compare with an explanation

No. r changes, so U changes. Its changes are balanced by opposite changes in K.

Now investigate one change Explore →

Predict. Change one thing. Explain.

Move a satellite marker around one ellipse. Compare K, U and E at the nearest, farthest and intermediate locations. Watch the radius and velocity directions; the central body is at a focus.

On narrow screens, swipe or scroll diagrams sideways to read all labels.

One ellipse: the marker moves around a fixed orbitcentral bodyTeal radius=2 m · orange velocity, speed=3 m/sGeometry: 37.5 units/m · velocity: 18 units per m/s

r=2 m; speed=3 m/s. K=4.5 J; U=-6 J. E=-1.5 J and L=6 kg·m²/s stay constant. Position control is not elapsed time.

Energy trades between K and U0+K4.5U-6E = K + U-1.5Energy (J) · same scale for every bar · full half-axis 6

One scaled orbit: GM=12 m³/s², m=1 kg, closest radius 2 m, farthest radius 6 m. Central body at a focus with radius below 2 m. Control is a geometric ellipse parameter, not a uniform clock. Drawing equations are not an additional lesson prerequisite.

Explain what you noticed: Which quantity changed? Which stayed fixed? Use the relevant physical relationship or contact condition to justify your prediction.

Apply the idea to a fresh problem Practice →

Show what you understand.

Two original questions are a starting check, not proof of mastery. Explain your choice before revealing the answer.

1. At ellipse endpoints r_a=3r_p. The speeds satisfy…

Show answer and reasoning

v_a=v_p/3. Endpoint angular-momentum conservation gives r_pv_p=r_av_a.

2. Which pair stays constant in the ideal elliptical orbit?

Show answer and reasoning

Total E and L. Gravity is conservative and exerts zero torque about the central body.

Original written challenge

4 points · self-check · not an official AP question

A 1 kg satellite has r_p=2 m, v_p=4 m/s and r_a=8 m in a scaled model with GM=20 m³/s². (a) Find L at periapsis. (b) Find v_a. (c) Calculate E at both endpoints. (d) Explain why gravity changes K but not L about the central body.

This response is not submitted or saved. Copy it before leaving.

Compare with the answer and four-point rubric
  1. 1 point: L=1×2×4=8 kg·m²/s.
  2. 1 point: v_a=8/(1×8)=1 m/s.
  3. 1 point: Near E=8−10=−2 J; far E=0.5−2.5=−2 J.
  4. 1 point: Gravity does work during radial motion, transferring energy between K and U, but its line of action passes through the central reference point, giving zero torque.

Accept equivalent correct methods and explanations. This is a Refresh Kid teaching rubric, not an official AP scoring guideline.

Recall the ideas without notes Review →

Retrieve it before you reveal it.

RECALL 1What stays constant in an ideal ellipse?

Total mechanical energy and angular momentum about the central body.

RECALL 2Where is speed largest?

At the closest point, periapsis.

RECALL 3When is |L|=mrv valid?

When velocity is perpendicular to the radius, including the near and far endpoints.

Revisit these tomorrow and a week later. Try a fresh problem and explain why the method applies.

An elliptical orbit: speed changes, E and L do not

  • Gravity only: E=K+U and angular momentum about the central body stay constant.
  • At near/far endpoints: r_pv_p=r_av_a.
  • General particle magnitude: |L|=mrv sinφ.

Remember: Do not use circular-orbit speed at arbitrary points of an ellipse. Also, mrv omits a needed sine factor away from perpendicular velocity.

Conditions: One scaled orbit: GM=12 m³/s², m=1 kg, closest radius 2 m, farthest radius 6 m. Central body at a focus with radius below 2 m. Control is a geometric ellipse parameter, not a uniform clock. Drawing equations are not an additional lesson prerequisite.

Refresh Kid · Unit 6 · Objectives 6.6.A · Review edition

Framework, scope and review status

Mapped to College Board CED, Topic 6.6, objectives 6.6.A. CED effective Fall 2024, current PDF ©2026; checked September 16, 2026. Fall-2026 corrections also checked. The lesson breakdown and questions are original Refresh Kid work, not official topic subdivisions.

Implementation and automated checks are separate from independent teacher review and observation of students. Both human review stages remain pending. This is a review edition, not a certified or validated assessment.

Optional further resource: College Board’s released questions and scoring guides. Papers can combine units; this link is an archive, not an assignment of every question to this lesson.

Our learn, explore, practice and recall sequence is informed by the IES learning guide. The exact Refresh Kid implementation has not been evaluated for learning effectiveness.

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